Or ax 1234h or 0ffh

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Web微机原理和接口技术习题答案解析第1章微机运算基础习题和思考题1. 请完成以下计算:17466d10101110.10101bae. a8h10101110101.01011b 1397.344d575.58h4bch010b bcd2. WebMOV AX,BҮТE1 AX=1234H AX= d. ADD DL,BYTE DX=0122H DX= e. INC DX DX=FF12H DX= f. INC DL DX=FF23H DX= g. XCHG AL,AH AX=1234H AX= h. SUB CL,CH CX=3451H CX= Question For each of the following unrelated instructions, show the result in the destination operand. Indicate if the instruction is invalid. Assume BYTE1 is defined as DB 05.

H:Appsdevelemu8086documentation8086 instruction set

http://service.scs.carleton.ca/sivarama/asm_book_web/Student_copies/ch6_arithmetic.pdf Webif using BX, the operand is defaultly located in Data segment,then: PA= (DS)*10H+ (BX)+ (DI)/ (SI)+disp if using BP, the operand is defaultly located in stack segment,then: PA= (SS)*10H+ (BP)+ (DI)/ (SI)+disp 16 f Based Indexed Relative Addressing MOV [BX+DI+1234H], AH 88 ;assume (ds)=4000h, (bx)=0200h, (di)=0010h ;machine code:88A13412h A1 list of all body parts

Answered: Q2) if DS-3456H,SS-234AH, IP ADFCH Mov… bartleby

WebMOV AX, 1234h RET ; return to caller. p1 ENDP CZSOPA unchanged CBW No operands Convert byte into word. Algorithm: if high bit of AL = 1 then: zAH = 255 (0FFh) else zAH = 0 Example: MOV AX, 0 ; AH = 0, AL = 0 MOV AL, -5 ; AX = 000FBh (251) CBW ; AX = 0FFFBh (-5) RET CZSOPA unchanged Clear Carry flag. Algorithm: CF = 0 8086 instructions Page 6 of ... WebFeb 4, 2024 · (2)将存储单元 3000h 和内容送至 4000h 单元。 (3)将累加器 aX 与寄存器 cx 中的内容对调. 答案：（1)mov aX， 1234H Mov ds, ax movAx, [3000H] mov [4000H], ax xchgax, cx 12.编程：将数据段中以 Bx 为偏移地址的连续单元的内容颠倒过来。 Webanswer bank (DX=FFFFh, AX=80C0h / shl ebx, 3 / shl ebx, 5) 18. What will be the hexadecimal values of DX and AX after the following instructions have executed? mov ax, 3456h mov dx, 12h mov bx, 10h div bx Choose one answer. a. DX=0006h, AX=2345h b. DX=1234h, AX=0056h c. DX=0056h, AX=1234h d. cannot be determined 19. list of all bob dylan songs

Answered: Instruction Before After а. MOV CX,25H… bartleby

微机原理课后习题解答 - 豆丁网

WebDec 31, 2024 · This instruction does more or less the opposite of MOV AX, [BX]: It writes data to memory. This time, the data in the register BX is written to the memory specified by the registers DS and AX. Because on x86 systems the low byte of some data is stored in the first byte and the high byte is stored in the second byte, the value 1234h would be ... WebTranscribed Image Text: Q2) if DS-3456H,SS-234AH, IP ADFCH Mov [2345H], 5675H Mov AX, 1234H ADD AX, [2345H] The final value of AX is A) 3579H b) 68A9H C) 3579D d) 1234H … images of hamstringWeb8. (5 points) Write a short sequence of instructions to store the contents of the CX register at theword memory location contained in CX. Thus if CX contains 1234h, the number 1234h will be stored at locations DS:1234h and DS:1235h in memory. mov bx,cx mov [bx],cx mov bx , cx mov [ bx ] , cx list of all bones in the body

"WebExample: MOV AL, 0FFh DAS RET ; AL = 0FFh (-1) ; AL = 99h, CF = 1. CZSOPA rrrrrr. Decrement. Algorithm: operand = operand - 1 Example: ... Example: MOV AX, 1234h PUSH AX POP DX ; DX = 1234h RET 8086 instructions. Page 41 of 53. CZSOPA unchanged. Push all general purpose registers AX, CX, DX, BX, SP, BP, SI, DI in the stack. Original value of SP … " - Or ax 1234h or 0ffh

Or ax 1234h or 0ffh

H:Appsdevelemu8086documentation8086 instruction set

http://site.iugaza.edu.ps/ayash/files/Assembly-Chapter7-Part2.pdf Weba. mov ax，12h b. mov ax，[1234h] c. mov ds：[1234h]，12h d. mov al，ds：[1234h] 5. 下面源程序语句中，_____包含有寄存器寻址方式。 ... and bx，0ffh and bh，[bx] 上述指令序列运行后，bx的内容是（）( b ) a. 0305h ( bcd ) a. mov al，00 b. and al，00 c. xor al，al d. sub al，al 10. 下面可以形成 ...

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WebJZ JNC JP JA JGE JLE Hand assemble the following codes: MOV BX, AX MOV BX, 01234H MOV BX [BP] MOV [SI+5] BX MOV [BX+SI], AL MOV AH, XYZ; Assume that XYZ is located … WebNov 21, 2024 · AX=FFFFh CF=1(result is not 0) SF=1 ZF=0 PF=1 OF=0 Question 2: a) Suppose that AX and BX both contains +ive numbers, and ADD AX, BX is executed , show that there is carry into the MSB but no carry out of the MSB if and only if, signed overflow occurs. Solution: As we know signed overflow occurs if and if: There is a carry into the …

WebNo, AX cannot store the value +32,768 because it is larger than a signed word. To determine if a value is valid or not, after the negation you would need to check the status flag to see … Webin the al register to the bl register, given ax =1234h and 3. assembly language instructions. (Total, P, Q and R are one byte long variables and are positive numbers). Total =P-Q+R 4. Determine if the following instructions are legal or not. This problem has been solved!

WebThe instruction, MOV AX, 1234H is an example of register addressing mode direct addressing mode immediate addressing mode based indexed addressing mode. … WebFeb 23, 2024 · Types of addressing modes: Register mode – In this type of addressing mode both the operands are registers. Example: MOV AX, BX XOR AX, DX ADD AL, BL. …

Webanswer bank (DX=FFFFh, AX=80C0h / shl ebx, 3 / shl ebx, 5) 18. What will be the hexadecimal values of DX and AX after the following instructions have executed? mov ax, 3456h mov …

WebIf AX-1234H and DX- 20FFH, list the sum and the contents of each flag register bit (C, S, and Z) after the ADD AX, DX instruction executes. 2. This problem has been solved! images of hamstersWebORG 100h LEA AX, m RET m DW 1234h END AX is set to: 0104h. LEA instruction takes 3 bytes, RET takes 1 byte, we start at 100h, so the address of 'm' is 104h. LES REG, memory Load memory double word into word register and ES. Algorithm: REG = first word; ES = second word; Example: ORG 100h LES AX, m RET m DW 1234h DW 5678h END AX is set … list of all bollywood movies 2022Web解答：（1）指令oR AX,1234H oR 0FFH 中的第一个oR 是指令系统中的“或”指令，而第二个oR 是表达式中表示逻辑“或”关系的。（2）指令oR AX,1234H oR 0FFH 中的第一个 . 26 . oR … list of all bollywood movies on amazon primeWebMar 26, 2024 · 1. @Linux The answer is FF00h: AL is incremented and wraps around from FFh to 00h, and AH is unchanged at FFh. Note that the "low", i.e. least-significant bits are written on the right. So for instance when AX = 1234h, you have AH = 12h and AL = 34h. … list of all bonanza episodeshttp://www.sce.carleton.ca/courses/sysc-3601/s14/SYSC3601-Slides-03-Intel%20Addressing%20Modes%20and%20Instruction%20Encoding.pdf images of hamstring in legWebmov ax,7FFFh add ax,2 ; SF = 1 ; Carry flag example: mov al,0FFh add al,1 ; CF = 1, AL = 00 ; Overflow flag example: mov al,+127 add al,1 ; OF = 1 mov al,-128 sub al,1 ; OF = 1 exit main ENDP END main Programming Exercises 1. Indicate whether or not each of the following instructions is valid. a. add ax,bx b. add dx,bl list of all bonnies fnafWebmov ax,dividendLow cwd; sign-extend dividend mov bx,divisor idiv bx (7.4.7 p8) What will be the contents of AX and DX after the following operation? mov dx,0 mov ax,222h mov cx,100h mul cx Ans.: DX = 0002h, AX = 2200h. (7.4.7 p9) What will be the contents of AX after the following operation? mov ax,63h mov bl,10h div bl Ans.: AX = 0306h. list of all bond films